Yes, but it will not be very “musette like”
Yup. I am not a physicist, so this could all be totally wrong, but...
The characteristic warble of the MM register is due to the "beating" effect of frequencies that are very close, but not exactly the same. This causes the peaks and valleys of the wave forms produced by each reed to go in and out of sync with each other.
Now the sound produced by each reed is not really single, pure frequency, but rather a stack of frequencies at certain multiples of the fundamental one. We say that, for example, A is tuned to 440 Hz, but that's just the lowest, fundamental frequency. What actually comes out when you play the note is a 440 Hz tone plus a quieter 880 Hz tone, an even quieter 1320 Hz tone, etc. An MM musette will have each of these frequencies from the one reed beating against its partner frequency in the other reed.
If you had an M reed with a detuned H reed and played an A, you wouldn't get any beating at the fundamental 440 Hz frequency, since only the M reed would be producing it. It wouldn't kick in until you got up to the 880 Hz level, as the quieter overtone (second harmonic) of the M reed beats with the fundamental of the H reed. Then the M reed's 1320 Hz tone (third harmonic) would again be all by itself, beating with nothing, since the next harmonic of the H reed wouldn't occur until around1760 Hz. And so on, up the harmonic spectrum.